Devi bought 8 m of ribbon.
she made 6 bows.
she used ⅝ m of ribbon for each bow.
how much ribbon did she have left

If devi bought 8 m of ribbon, and used 5/8 m for 6 bows then she has 2 m of that bow left  

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.

1.17+3.99a. you combine the terms with a to create 3.99 and the 1.17 stays because it has no like terms or a variable