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Mathematics, 25.09.2019 00:50 jameslinimk

(01.01) kisha and rae are asked to solve βˆ’5x βˆ’ 14 = 2x + 7. identify where one of them made an error.
kisha
βˆ’5x βˆ’ 14 = 2x + 7
βˆ’5x βˆ’ 14 βˆ’ 2x = 2x + 7 βˆ’ 2x
βˆ’7x βˆ’ 14 = 7
βˆ’7x βˆ’ 14 + 14 = 7 + 14
βˆ’7x = 21
negative 7x over negative 7 equals 21 over negative 7
x = βˆ’ 3
rae
βˆ’5x βˆ’ 14 = 2x + 7
βˆ’5x βˆ’ 14 + 5x = 2x + 7 + 5x
βˆ’14 = 7x + 7
βˆ’14 + 7 = 7x + 7 + 7
βˆ’7 = 7x
negative 7 over 7 equals 7x over 7
x = βˆ’ 1
rae made the error when she added 7
rae made the error when she added 5x
kisha made the error when she subtracted 2x
kisha made the error when she divided by βˆ’7

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(01.01) kisha and rae are asked to solve βˆ’5x βˆ’ 14 = 2x + 7. identify where one of them made an error...
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