Abag contains 10 blue, 6 green, and 4 red marbles. you choose one marble. without putting it back, you choose a second marble. what is the probability that you first choose a green marble and then a blue marble?

Step-by-step explanation:

Given :

A bag contains 10 blue, 6 green, and 4 red marbles.

You choose one marble. Without putting it back, you choose a second marble.

To Find: What is the probability that you first choose a green marble and then a blue marble?

Solution:

No. of blue balls = 10

No. of green balls =6

No. of red marbles =4

Total no. of marbles = 10+6+4 =20

Since we are given that first he choose a green marble

So, probability of getting green marble :

=

Since he choose second marble without replacement

So, after choosing first ball . The total no. of balls will be 19

So, Probability of getting blue marble in second draw :

=

The probability that you first choose a green marble and then a blue marble:

Hence the probability that you first choose a green marble and then a blue marble is  

4400

step-by-step explanation:

ask the math teacher she or he would know lol.

step-by-step explanation: