At a checkers tournament there where 64 players. it was elimatation tournament. how many games where played before there was a winner

So first game
half were eliminated
we notice a pattern
first game=64 times 1/2
next game 32 times 1/2 so

so just multiply by 1/2 till you get 1
round 1 64/2=32
round 2  32/2=16
round 3  16/2=8
round 4  8/2=4
round  5 4/2=2
round 6  2/2=1

6  is the answer

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)