Mellissa plotted the graph of a function. the function contains the points (2, 4) and (3, 6). the domain of the function is all whole numbers. mr. wilson reviewed her work and said that the graph is incorrect. explain why this graph is incorrect.
draw a correct graph.

Graph is incorrect because she made the domain finite whereas according to the question domain is infinite that is all whole numbers.

Step-by-step explanation:

Mellissa plotted  two given points  which is (2,4) and (3,6).

she drew a line segment by the two points whereas, she was suppose to draw a line.

Because this line can be extended upto any point. She violated the rule that domain of the function is all whole numbers because she made it finite

Whereas domain is infinite as per given in the question.

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.