Question 1: car a began a journey from a point at 9 am, traveling at 30 mph. at 10 am car b started traveling from the same point at 40 mph in the same direction as car a. at what time will car b pass car a?
solution:
let after t hours the distances d1 traveled by car a
=> d1 = 30 t
car b starts at 10 am and will therefore have spent one hour less than car a when it passes it.
after (t - 1) hours, distance d2 traveled by car b
=> d2 = 40 (t - 1)
when car b passes car a, they are at the same distance from the starting point and therefore d1 = d2
=> 30 t = 40 (t - 1)
solve the equation for t,

15: 24

62.5%

step-by-step explanation:

(a) common ratio in the given sequence is, 3

(b) push ups will do kendall do on the 20th week

step-by-step explanation:

geometric sequence is a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio(r)

(a)

given the sequence: 6 , 18 , 54 , 162 ,

this sequence is geometric sequence where each term is 3 times the previous term.

therefore,

common ratio(r) = 3.

(b)

a formula for nth term of geometric sequence is given by;

,   where r is the common ratio between the successive terms and is the first term,

to find how many push ups will kendall do on the 20th week.

here. n = 20th term.

in the given sequence first term

then;

simplify:

therefore, push ups will do kendall do on the 20th week