Suppose an investment of $1,800 doubles in value every 7 years. how much is the investment worth after 42 years?

The investment in 42 years will become $115199.88

Step-by-step explanation:

Let the investment model is

A = final amount

P = initial amount

r = rate

t = time

Now, given that

P = $1800

A = 2P = 2×1800 = $3600

t = 7 years

Now, we have to find A for t = 42 years

Hence, the investment in 42 years will become $115199.88

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