Idon't understand how to the problem

We have:

(30x²+23x+16)/(cx+3) - 13/(cx+3) = 6x+1

(30x²+23x+16 - 13)/(cx+3) = 6x+1

(30x²+23x+3)/(cx+3) = 6x+1

30x²+23x+3 = (cx+3)(6x+1)

30x²+23x+3 = 6cx²+cx+18x+3

30x² + 23x + 3 - 6cx² - cx - 18x - 3 = 0

(30 - 6c)x² +(5 - c)x = 0

6(5 - c)x² +(5 - c)x  = 0

(5 - c)(6x² +x) = 0, and x∈ R\ {3/c} ⇒ 5 - c = 0 ⇒ c = 5.