Which point is not on the line y = 5x + 1?
(1, 6)
(2, 11)
(0, 1)
(-1, 6)

To find which point is NOT on the line y = 5x + 1, we just need to plug each point into equation y=5x+1 to see which one point satisfies this equation.

check for (1,6)

y=5x+1

or 6=5*1+1

or 6=5+1

or 6=6

Which is TRUE.

check for (2,11)

y=5x+1

or 11=5*2+1

or 11=10+1

or 11=11

Which is TRUE.

check for (0,1)

y=5x+1

or 1=5*0+1

or 1=0+1

or 1=1

Which is TRUE.

check for (-1,6)

y=5x+1

or 6=5*(-1)+1

or 6=-5+1

or 6=-4

Which is FALSE.

Since only point (-1,6) fails to satisfy the given equation hence point (-1,6) is the final answer.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3