Devin is asked to write out how to find the circumference of a circle. he writes:
"first measure the radius, then multiply that by 2, then multiply that answer by π, and that will give you the circumference."
which statement is another correct response?
a) first measure the radius then multiply that by π to find the circumference.
b) first measure the diameter then multiply that by π to find the circumference.
c) first measure the radius, then divide that by 2, then multiply that answer by π to find the circumference.
d) first measure the diameter, then divide that by 2, then multiply that answer by π to find the circumference.

Option B is correct

First measure the diameter then multiply that by π to find the circumference

Step-by-step explanation:

Circumference of a circle is given by:

or

where

C is the circumference of a circle

r is the radius of the circle

D is the diameter of a circle.

As per the statement:

He writes:

"First measure the radius, then multiply that by 2, then multiply that answer by π, and that will give you the circumference."

⇒

We know that:

Diameter of a circle(D) = 2r

then;

⇒First measure the diameter then multiply that by π, to get the circumference.

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}