Astone is thrown upward from ground level with what minimum speed should the stone be thrown so as to reach a height of 9 feet?

***this is a calculus problem not a physics one. i need figuring out how to solve this using the equation h(t)=-16t^2-vt-h
you!

The stone should be thrown with minimum speed 24 feet/s so as to reach a height of 9 feet

To solve this problem there are several basic principles in Derivatives that need to be recalled, namely:

Let us now tackle the problem !

Given:

The stone is thrown upward from ground level → h o = 0

We will differentiate above equation to get the instantenous velocity of the stone.

At maximum height → v(t) = 0

→ Equation 1

Let the maximum height h(t) = 9 feet , then :

← Equation 1

Grade: High School

Subject: Mathematics

Chapter: Differentiation

Keywords: Maximum , Minimum , Value , Function , Variable , Derivation , Differentiation

answer: 60

step-by-step explanation:

1/2a + (2/3×30)   = 50

1/2a + 20 = 50

1/2a = 30

a = 60

32

step-by-step explanation: