The distance from charles’s house to his school is 3 miles. his father gave him a ride for 1,760 yards, and he walked the rest of the way. the distance that charles walked is either
1
1.5
or 2 miles,
or 1,760
2,000,
3,520 yards.
(hint: 1 mile = 1,760 yards.)

the answer is 21%.

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %