Joanne bought 3 baseball cards for $160. if the first card was as expensive as the combined price of the second and the third cards, and the second card cost $20 more than the third card, what is the price of the first card?

Let b represent the third card
let (b+20) represent the second card
let (2b+20) represent the first card

(2b+20)+(b+20)+b=160
                   4b+40=160
                          4b=160-40
                          4b=120
                       4b/4=120/4
                             b=30

   2b+20 
= 2(30)+20
= 60+20
= 80

   b+20
= 30=20
= 60

Therefore, the first card was $80, the second card was $50 and the third card was $30.