Ff(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

(g – f)(3) =  23.

Step-by-step explanation:

Given  :  f(x) = 4 – x² and g(x) = 6x .

To find : which expression is equivalent to (g – f)(3).

Solution : We have given   f(x) = 4 – x² and g(x) = 6x .

(g – f)(3) = g (3 ) - f(3) .

g(x) = 6x

Plug x = 3 .

g(3) = 6 *3 .

g(3) =  18.

For    f(x) = 4 – x².

Plug x = 3

f( 3) = 4 – (3)².

f(3) = 4 – 9.

f(3) =  –5.

Then , (g – f)(3) = g (3 ) - f(3) .

Plugging the values

(g – f)(3) = 18 - (-5) .

(g – f)(3) = 18 + 5.

(g – f)(3) =  23.

Therefore,  (g – f)(3) =  23.

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.