The measures of the angles in △abc are given by the expressions in the table.

angle measure
a 65°
b (3x−10)°
c (2x)°
find the value of x. then find the measures of angles b and c.

enter your answers in the boxes.
x =

m∠b=
º

m∠c=
º

We know that the summation of angles of a triangle is 180°. Then we can measure angles of B and C by,
m∠A + m∠B + m∠C=180° 
65° + (3x−10)° + (2x)°=180°
Solve for variable x by transposing and combing same terms,
5x=180°- 65°+ 10° 
x=125/5, x=25
Since we already know the value of x, we can proceed in solving B and C
B=(3x−10)°=3(25)-10=65 
C=2x=2(25)=50
Therefore, the answers are x=25, B=65 and C=50.

 the summation of angles of a triangle is 180°.  measure angles of B and C by,
m∠A + m∠B + m∠C=180° 
65° + (3x−10)° + (2x)°=180°
5x=180°- 65°+ 10° 
x=125/5, x=25
B=(3x−10)°=3(25)-10=65 
C=2x=2(25)=50

Ithink the answer is c