How do i find the area and perimeter this trapezoid

Area=(1/2)(b1+b2)h

b1=55
b2=28
h=19

aera=(1/2)(55+28)(19)
area=(1/2)(83)(19)
area=788.5 in²

perimiter is length areound
it is 55+21+28+21=125in

The area is 788.5
the formula to find a trapezoid is 2h(b₁+b₂)
to substitute that, i would be 2(19)(55+28)
the answer to that is 788.5
the perimeter is 125.
to find the perimeter, u need o add all the sides to get the perimeter.
the formula is P=a+b+c+d
to substitute that it would be 55+28+21+21.
the answer to that is 125. 

Using the rise/run rule. you would get 2/6.simp. 1/3