What are the vertical asymptotes of the function f(x) = the quantity of 4 x plus 8, all over x squared plus 3 x minus 4?

4x+8/x^2+3x-4 
Vertical asymptotes are vertical lines which correspond to the zeroes of the denominator of a rational function.

the vertical asymptotes (which tell me where the graph can not go) will be at the values 
4x+8/x^2+3x-4

if u solve the denominator x should not eqaul to 0

so x^2+3x-4=0 x=1,x=-4

I’m not absolutely sure but i think it’s 7x6x5x4x3x2=5040 because as the first character you can take any of the 7 given then you are left with 5 then 6 then 4 etc.