The area of a rectangle is 56 cm. the length is 2 cm more than x and the width is 5 cm less than twice x. solve for x. round to the nearest whole number

x = 6

Step-by-step explanation:

Given : The area of a rectangle is 56 cm². The length is 2 cm more than x and the width is 5 cm less than twice x.

We have to find the value of x.

Given area of rectangle = 56 cm²

Length  is 2 cm more than x  mathematically written as

L = 2 + x

Width is 5 cm less than twice x  mathematically written as

W = 2x - 5

Thus, we know area of rectangle = length × width

Substitute, we  have,

56 = (2 + x)(2x - 5)

Multiply each term of first bracket with each term of second bracket , we have,

Simplify, we have,

Subtract 56 both sides, we have,

Simplify , we get,

Using quadratic formula for the general equation , we have

Simplify, we get,

Also,

We get,

Thus,

Simplify, we get,

Since, x has to be whole number so x = 6

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation: