The driver of a car traveling at 50 ft/sec suddenly applies the brakes. the position of the car is s(t) = 50t - 2t2, t seconds after the driver applies the brakes. how many seconds after the driver applies the brakes does the car come to a stop?

The car come to a stop in 12.5 seconds after the driver applies the brakes

Step-by-step explanation:

Given :The position of the car is , t seconds after the driver applies the brakes.

To Find : How many seconds after the driver applies the brakes does the car come to a stop?

Solution:

Where V is Speed of car

So,

So,Speed of the car is  

Now we are supposed to find How many seconds after the driver applies the brakes does the car come to a stop.

So, Substitute V = 0

Hence the car come to a stop in 12.5 seconds after the driver applies the brakes

answer: 12

step-by-step explanation:

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.