Which polynomial is written in standard form for the polynomial 3x^4+x^6-10+5x?
a. 3x^4+x^6-10+5x
b. x^4(x²+3)+5(x-2)
c. x^6+3x^4+5x-10
d. -10+5x+3x^4+x^6

Standard form is add all ike terms and orderin exponent form, highest to lowest

we move the x^6 front and 3x^4 after that, then we do the 5x then -10

x^6+3x^4+5x-10

C is answer

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

than do 23.50 times 18 and then divide your answer by 100 than you will get x.