Write an equation for the line perpendicular to y = 3x – 5 that contains (4, –2).
a.
y + 2 = -1/3(x – 4)
c.
y + 4 = -1/3(x – 2)
b.
y + 2 = 3(x – 4)
d.
x + 2 = 3(y – 4)

y = 3x – 5 
slope = 3
perpendicular slope = -1/3

equation
y+2 = -1/3(x-4)

answer is a.
y + 2 = -1/3(x – 4)

Here, Equation: y = 3x - 5
Here, slope = 3
Perpendicular line slope = -1/3  [ Opposite & reciprocal ]

Now, y - y1 = m( x - x1)
y + 2 = -1/3 (x - 4)

In short, Your Answer would be Option A

Hope this helps!

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