Let f(x) = 2x – 1, g(x) = 3x, and h(x) = x2 + 1. compute the following.
1. f(g(-1))
2. f o h(3)
3. g(f(-5))

1.  g(-1) =  -3

f(-3) =  2(-3) - 1 =  -7

2. f o h(3) :-
h(3) =  3^2 + 1 = 10
f o h(3) =   2(10) - 1 = 19

3.   f(-5) =  -11
g(f(-5)) = g(-11) = -33

For number 3, We can do the same thing as we did for number 1. First of all, we start from f(- 5), which means we have to replace x with - 5. So f(- 5) = 2 * - 5 - 1 = - 10 - 1 = - 11. So now we are looking for g(- 11), and we also substitute x for - 11 here, so g(- 11) = 3 * -11 = - 33. So our answer is - 33.
About question 2, I don't know what that o is for.
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