What is the equation of the line (in point-slope form) that is parallel to y+2=−7(x+3) and passes through the point (1,4)?

y+1=−7(x−4)
y+4=7(x+1)
y−1=−7(x+4)
y−4=−7(x−1)
y−4=7(x−1)

  y−4=−7(x−1)

Step-by-step explanation:

The point-slope form of the equation for a line with slope m through point (h, k) is ...

  y -k = m(x -h)

Your given line has a slope of -7. The parallel line will have the same slope.

So, you want to fill in the above form with m=-7, (h, k) = (1, 4):

  y -4 = -7(x -1)

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .