Calculate the area of the figure below using the following information: area of triangle abc = 31.8 square units area of triangle acd = 39.2 square units area of triangle aed = 35.5 square units image of irregular pentagon with vertices points a, b, c, d, and e starting at upper left moving clockwise. two dotted diagonal lines, one connecting vertices a and c, and the second connecting vertices a and d. the area of the figure abcde is square units. answer for blank 1:

Area of irregular pentagon=106.5 square units.

Step-by-step explanation:

It is given that Area of triangle ABC = 31.8 square units,

Area of triangle ACD = 39.2 square units and

Area of triangle AED = 35.5 square units.

Thus, ABCDE makes an irregular pentagon, therefore

Area of irregular pentagon= Area of triangle ABC +Area of triangle ACD+Area of triangle AED

⇒Area of irregular pentagon=31.8+39.2+35.5

⇒Area of irregular pentagon=106.5 square units.

Thus, area of an irregular pentagon is 106.5 square units.

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step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

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m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0