Xavier is x years old and yvonne is y years old. yvonne is 7 years older than xavier. four times yvonne’s age is equal to 200. (a) write an equation that could be used to solve for yvonne’s age, y. (b) how old is yvonne? show your work and don’t forget the unit. (c) how old is xavier? show your work and don’t forget the unit

X+7= Yvonne's age.

a. 4(x+7)=200

b. 4(x+7)=200
4x+28=200
4x=172
x=43
Yvonne is 43 years old.

c. 43-7=Xavier's age.
36
Xavier is 36 years old.

You would have to write an equation. I would use the equation 4y=200. Thats your answer for (a). Then reverse the equation and solve to figure out the answer to (b). What we do to one side we do to other, right? So we would divide each side by 4. That leaves us with y=50. There's your answer to (b). Now to find Xavier's age we would simply do Yvonne's age minus 7. 50-7=43. There's your answer to (c).
A) 4y=200
B) 50 years old
C) 43 years old
Hope this helps