Arectangle has a perimeter of 56 cm. if w. e were to add 5 cm to the width and subtract 5 cm from its length we would have a square. find the length and width.

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

i think the correct option is the second option.