Cylinder a has a radius of 4 inches and a height of 2 inches. cylinder b has a radius of 2 inches. what is the height of cylinder b to the nearest inch if both cylinders have the same volume?

h=8 in

Step-by-step explanation:

Formula: V=pi r^2 h

Cylinder A:

radius: 4 in  height: 2 in

V=pi*4^*2*2

V=pi*16*2

V=pi*32

V=3.14*32

V=100.48

Cylinder B:

radius: 2 in  height: ?  volume: 100.48

100.48=pi*2^2*h

100.48=pi*4*h

100.48=3.14*4*h

100.48=12.56*h

100.48/12.56=h

h=8 in

Hope this helps :)

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752