Write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation (2,-2): y=-x-2 i have no idea. i am struggling so bad with this

Okay, let's start with the given equation.
y=-x-2
The slope of that line would be -1
A line parallel to this would have the same slope of -1
Slope intercept form is y=mx+b
"m" is the slope and "b" is the y-intercept.
Substitute the given x and y values from the given point and the slope into this equation.
x=2, y=-2, m=-1 and we are solving for b
You then have:
-2=-1(2) + b
-2 = -2 + b
b= 0
Now, we have the y-intercept and the slope, which is all we need to create the equation
b=0, m=-1
Final  y=-x + 0 :)

What's the denominator