if p(x, y) is the point on the unit circle defined by real number theta , then cot
theta=
x/y
y/x
1/x
1/y

The point P forms a triangle with
base length x (adjacent to our angle theta)
and height y (opposite our angle theta)
and hypotenuse 1 (because the radial length of the unit circle is 1).

cotangent theta = adjacent / opposite
cotangent theta = x / y

Sorry can't answer that question

step-by-step explanation:

yes it is1. move over 2 points on the x-axis2. move over 2 points on the y-axis