then![\mathsf{f(a+h)-f(a)}\\\\ =\mathsf{\big[3(a+h)+1]-(3a+1)}\\\\ =\mathsf{\big[3a+3h+1]-3a-1}\\\\ =\mathsf{\diagup\!\!\!\!\! 3a+3h+\diagdown\!\!\!\! 1-\diagup\!\!\!\!\! 3a-\diagdown\!\!\!\! 1}\\\\ =\mathsf{3h}\quad\longleftarrow\quad\textsf{this is the answer.}](/tpl/images/0286/0267/b2b7d.png)
If ƒ(x ) = 3x + 1, then ƒ(a + h ) - ƒ(a ) =
h
3h
3h + 2...
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