In the below system, solve for y in the first equation.
x − 3y = −6
2x − 7y = 10
a. 1/3x+2
b. -1/3x+6
c. -x+2
d. -1/3x+2

The answer is the option A

Step-by-step explanation:

we have

-----> first equation

-----> second equation

Solve for y in the first equation

That means------> isolate the variable y in the first equation

Divide by both sides

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles