The a value of a function in the form f(x) = ax2 + bx + c is negative. which statement must be true?

the vertex is a maximum.

the y-intercept is negative.

the x-intercepts are negative.

the axis of symmetry is to the left of zero.

A) the vertex is a maximum.

Step-by-step explanation:

The function f(x) = ax^2 + bx + c, where is "a" is negative.

a < 0, means the graph of the parabola opens down. when the parabola opens down we will have the vertex as a maximum point.

Therefore, answer is A) the vertex is a maximum.

Hope this will helpful.

Thank you.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."