Will upvote
newton’s law of cooling states that for a cooling substance with initial temperature t0 , the temperature t(t) after t minutes can be modeled by the equation t(t)=ts+(t0−ts)e−kt , where ts is the surrounding temperature and k is the substance’s cooling rate.
a liquid substance is heated to 80°c . upon removing it from the heat it cools to 60°c in 12 minutes.
what is the substance’s cooling rate when the surrounding air temperature is 50°c ?
round the answer to four decimal places.
0.0687
0.0732
0.0813
0.0916