If the sin 60° is square root 3 over 2, then the cos ° = (4 points)

30° ; square root 3 over 2
60° ; 1
60° ; square root 2 over 2
30° ; 1 over 2

You have a right triangle, in this triangle you have the following angles:30º, 60º and 90º.

sin 60º=√3/2
Then:
side opposite to 60º is √3
hypotenuse =2
Side oposite:
hypotenuse²=adjacent²+opposite²
2²=adjacent²+(√3)²
adjacent²=4-3
adjacent²=1
adjacent=√1=1
side adjacent to 60º=1

cos 30º=side adjacent/ hypotenuse
side adjacent to 30º=√3
hypotenuse=2

Cos 30º=√3/2

cos 60º=side adjacent/ hypotenuse
side adjacent to 60º=1
hypotenuse=2

Cos 60º=1/2

cos 30º=√3 /2