What are the intercepts of the line 2x + 4y = 12?

a. x-intercept: 6; y-intercept: –3 b. x-intercept: 6; y-intercept: 3 c. x-intercept: –6; y-intercept: 3 d. x-intercept: –6; y-intercept: –3

For x-intercepts, you plug 0 for y and solve for x, and vice versa for y-intercepts.

X: 2X+4(0)= 12
2x= 12
12/2= 6 so the x intercept is 6. 

Y: 2(0)+4Y=12
4y= 12
12/4= 3 so the y intercept is 3.

Your answer is B. x-intercept: 6; y-intercept: 3

The answer is B. if you make the x zero to find the y-int it would be 3 and if you make the y zero to find the x-int it would be be x-int= 6 y-int=3