Y=x+1
3x-2y=5

solve using substitution

(4, 5) 
Work:
Substitute the y in the second problem with y=x+1
3x-2(x+1)=5
3x-2x+1=5
x=4
Now solve for y
y=4+1
y=5

1st: You plug x+1 in for the value of y of the equation 3x-2y=5
2nd: Then you solve the equation 3x-2(x+1)=5
You will need to distribute the -2 into the x and 1 that is in the parentheses
You will then get 3x-2x-2=5
Then combine like terms which are 3x and -2x
You get x-2=5, then you will just add the 2 to both sides so then you will get x=7
3rd:Then you substitute the 7 that you just got in for the value of x for the equation y=x+1
4th:The equation would now be y=(7)+1
So then you will just add 7 and 1 together and you get y=8
*Your final answer is (7,8)*

It’s 24.6 after you round to the nearest tenths the answer should be 25.0