Graph f(x) = 2x^4+3
let x = 0, 1, and 2.
show your work

Sub those points for x
f(x) is the y

(x,y)

so for x=0
f(0)=2(0)^4+3
f(0)=0+3
f(0)=3
(0,3) is a opint

for x=1
f(1)=2(1)^4+3
f(1)=2(1)+3
f(1)=2+3
f(1)=5
(1,5) is another point

for x=2
f(2)=2(2^4)+3
f(2)=2(16)+3
f(2)=32+3
f(2)=35
(2,35) is another point

points are
(0,3)
(1,5)
(2,35)