Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. a(n)=-6+(n-1)(1/5)

a. 5, -5 1/5, 1 4/5.
b. -6, -5 1/5, -4
c. 0, 3/5, 1 4/5
d. -6, -5 2/5, -4 1/5

i dont understand the question? ?

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752