Jason and sheldon are neighbors who work for the same accounting firm. they leave the office at the same time. after t seconds, jason's distance from the office in meters is given as 4 more than 3 times t, while sheldon's distance from the office is 6 more than 2 times t.
the function that represents the total distance d(t) that jason and sheldon cover together in t seconds is given by d(t) = t - 2 t + 2 5t - 10 5t + 10 . in 7 seconds, jason and sheldon together cover a distance of 5 9 25 45 meters.