Mathematics, 03.02.2020 10:53 3jazybraxy
David found and factored out the gcf of the polynomial 80b4 – 32b2c3 + 48b4c. his work is below. gfc of 80, 32, and 48: 16 gcf of b4, b2, and b4: b2 gcf of c3 and c: c gcf of the polynomial: 16b2c rewrite as a product of the gcf: 16b2c(5b2) – 16b2c(2c2) + 16b2c(3b2) factor out gcf: 16b2c(5b2 – 2c2 + 3b2) which statements are true about david’s work? check all that apply. the gcf of the coefficients is correct. the gcf of the variable b should be b4 instead of b2. the variable c is not common to all terms, so a power of c should not have been factored out. the expression in step 5 is equivalent to the given polynomial. in step 6, david applied the distributive property.
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David found and factored out the gcf of the polynomial 80b4 – 32b2c3 + 48b4c. his work is below. gfc...
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