Write the standard form of the line with the given information. include your work in your final answer. type your answer in the box provided or use the upload option to submit your solution. the line that contains a slope of and passes through the point (-2, -3).

I am going to show you the procedure with any slope (given that you did not write the value of the slope)

general slope value: m
generic point (x1,y1)

Formula: y - y1 = m (x -x1)

y - y1 = mx - mx1

y - mx - y1 + mx1 = 0

x1 = -2 , y1 = -3 =>

y - mx - (-3) + m(- 2) = 0

y - mx + (3 -2m) = 0

Now suppose a value for m. Lets say it is m = 5.

y - 5x + (3 - 2*5) = 0

y - 5x + (3 - 10) = 0

y - 5x + (-7) = 0 and that is the standard form if the slope is 5. Now you can do the same with any slope.

Abcd stupid son of a bitxh