The sum of 3 consecutive integers is 138, what are the integers?

Let's call the consecutive integers a, a+1, and a+2.
they add up to 138: a+(a+1)+(a+2)=3a+3=138
now you have an equation: 3a+3=138
subtract 3 from both sides: 3a=135
divide both sides by 3: a=45
so the consecutive integers are 45, 46, and 47

Idon’t know what the answer is i wish i could