Aswimming pool charges $6 for adults and $4 for children. on a particular day, they made $1,326 in admissions. if a total of 289 people paid to swim, how many kids and how many adults

Children:  204

Adults:  85

Step-by-step explanation:

Representation:  let k represent the number of children and a the number of adults.  

Equations:  k + a = 289 (numbers of people)

                   ($4/child)k + ($6/adult)a = $1,326

Let's solve this system of equations by substitution. Since k + a = 289, a = 289 - k.  Substituting 289 - k for a above, we get this equation in one variable:

($4/child)k + ($6/adult)(289 - k), or, without units, 4k + 1734 - 6k = 1326.

The next step is to combine like terms:  -2k = -408.

Dividing both sides by -2, we get k = 204.  There are 204 children in the pool and 289 - 204 adults, or 85 adults.

Children:  204

Adults:  85

this is false ^.^ lol

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!