Jared wanted to find three consecutive even integers whose sum was 4 times the first of those integers. he let k represent the first integer, then wrote and solved this equation: k+ (k+1) + (k+2) = 4k. did he get the correct answer? explain

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Instead of k, k+1, k+2, you should use k, k+2, k+4 with the constraint that k is even (i.e. if you return an odd integer for k, or a non-integer, then return no solution). 

k + (k+2) + (k+4) = 4k

3k + 6 = 4k
k = 6 

Indeed, 6+8+10 = 4*6.

The answer to the question is d