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Mathematics, 03.02.2020 22:03 yola32

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i think it's step one, but i'm not sure.

the work of a student to solve a set of equations is shown:

equation a: y = 15 βˆ’ 2z
equation b: 2y = 3 βˆ’ 4z

step 1: βˆ’2(y) = βˆ’2(15 βˆ’ 2z) [equation a is multiplied by βˆ’2.]
2y = 3 βˆ’ 4z [equation b]
step 2: βˆ’2y = 15 βˆ’ 2z [equation a in step 1 is simplified.]
2y = 3 βˆ’ 4z [equation b]
step 3: 0 = 18 βˆ’ 6z [equations in step 2 are added.]
step 4: 6z = 18
step 5: z = 3

in which step did the student first make an error?

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Answers: 2

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i think it's step one, but i'm not sure.

the work of a...
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