What is the sum of a 6-term geometric series if the first term is 24 and the last term is 1,417,176?

First, we need to solve for the common ratio from the data given by using the equation.

a(n) = a(1) r^(n-1)
1417176 = 24 r^(6-1)
59049= r^5
r = 9

We can find the sum by the expression:

 S(n) = a(1) ( 1 - r^n) / 1-r

where a(1) is the first term, r is the ratio and n is the number of terms.

S(9) = 24 (1 - 9^6) / 1-9
S(9) = 1594320

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