Hurry whoever answers first will be the
what is the equation of the line that is parallel to the line y − 1 = 4(x + 3) and passes through the point (4, 32)?

a. y = –x + 33
b. y = –x + 36
c. y = 4x − 16
d. y = 4x + 16

The line is y-1=4(x+3).
For the line to be parallel, it need to have the same slope.
And because this line is already in slope intercept form, the slope is 4.
So make the equation for the line.
y=4x+b
Then plug in the coordinate (4,32) for x and y to find b.
32=4(4)+b
32=16+b
b=32-16=16
So the final equation is:
y=4x+16
D. y=4x+16

Hope this helps :)