Given that 3 to the power of -n= 0.2 find the value of (3 to the power of 4) to the power of n.
so 3^-n=0.2 find value of (3^4)^n my working out: 1)3=n surd 0.2 2)n must be decimal number 3) cuberoot o.2=0.5848035476425733 4)so n=0.5848035476425733 5)(3^4)^0.5848035476425733=13.06438 01669 6) so that answer is the value of (3^4)^n