Find the number of positive integral solutions of abc=45.

45=1×5×9 so 45×1×1=45. 5×9×1=45. 9×5×1=45. 45×1×1=45 .and ,then 1×5×9=45 sooo if ABC are treated as identical variables number of solutions can be those 5 steps about to find all the number of positive integral solutions ...

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