Jimthompson5910 is such a great and so important in making a differnce here.

a given line has the equation 2x + 12y = −1.

what is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?

y = ( )x + 9

6

Step-by-step explanation:

find the gradient of the line using the y=mx +c method rearrange 2x+12y=-1 to become 12y=-2x-1...divide both sides by 12 so m=-1/6. To find the slope of a line perpendicular to 2x+12y=-1 when their slopes multiply they give -1. The gradient of the perpendicular line is 6. Using the point it passed through (0,9) use the equation of a line formula which would be y-9/x-0=6

cross multiply and you'll get y=6x+9

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb